Question

A train starts from rest and accelerate uniformly at the rate of 5 m/s^2 for 5sec.Calculate the velocity of train in 5sec​

Answer 1

Answer:

The velocity of train in 5 sec is 25 m/s.

Explanation:

Given:

• u = 0

• a = 5 m/s$^{2}$

• t = 5 sec

where u means initial velocity

a means acceleration

and t means time.

To find:

Velocity of train.

Solution:

Using Newton's first law of motion, we will find the velocity.

v = u + at

where v means final velocity

u means initial velocity

a means acceleration and t means time.

Now, substitute the known values, we get

v = 0 + 5 × 5

→ v = 0 + 25

→ v = 25 m/s

Thus, velocity of train in 5 s is 25 m/s.

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More formulas:

1. Newton's first law of motion -

v = u + at

2. Newton's second law of motion -

S = ut + 1/2 at$^{2}$

3. Newton's third law of motion -

v$^{2}$ = u$^{2}$ + 2as

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Answer 2

Answer:

v=25m/s is the answer .....