Question

A train starts from rest and accelerate uniformly at the rate of 5 m/s2 for 5 sec.Calculate the (a) distance travelled by train in 5 sec. (b) velocity of train at the end of 5 sec​

Answer 1

Given :

• A train starts from rest and accelerate uniformly at the rate of 5 m/s2 for 5 sec.

To Find :

• a) The distance travelled by the train in 5sec.
• b) Velocity of the train at the end of the 5sec.

Solution :

In this question, Intial Velocity , Acceleration and Time are given and we have to find the final velocity.

Intial Velocity of the train, u = 0 m s⁻¹

Final Velocity of the train, v = ?

Acceleration, a = 5 m s⁻²

Time, t = 5 sec

Distance travelled, S = ?

a) To find the distance travelled, we use the equation, S = ut + ½ at²

• S = ut + ½ at²
• S = 0 × 5 + ½ × 5 × (5)²
• S = 0 + ½ × 5 × 5 × 5
• S = 0 + ½ × 5 × 25
• S = 0 + ½ × 125
• S = 0 + 62.5
• S = 62.5 m

b) To find the final velocity, we use the equation, v = u + at

• v = u + at
• v = 0 + 5 × 5
• v = 0 + 25
• v = 25 m s⁻¹

Therefore :

• The distance travelled by the train in 5sec is 62.5 m
• Velocity of the train at the end of the 5sec is 25 m s⁻¹

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