Question

A train starts from rest and accelerate uniformly at the rate of 5m/second square for 5 seconds then calculate the velocity of the train

Answer 1

$\large \dag$ Question :-

A train starts from rest and accelerate uniformly at the rate of 5m/second square for 5 seconds then calculate the velocity of the train

$\large \dag$ Answer :-

$\red\dashrightarrow\underline{\underline{\sf  \green{Final   \: Velocity \:  of\: train  \: is \:  25\: m/s }} }$

$\large \dag$ Step by step Explanation :-

Here We Have,.

Initial Velocity = u = 0 m/s

Acceleration = a = 5 m/s²

Time = t = 5 s

⇝ Calculating Final Velocity :-)

Let Final Velocity be = v m/s

❒ We Have 1st Equation of Motion as :

$\large \bf \red\bigstar \: \: \orange{ \underbrace{ \underline{v = u + at}}}$

⏩ Applying 1st Equation of Motion ;

$:\longmapsto \rm v = 0 + 5 \times 5$

$:\longmapsto \rm v = 0 + 25$

$\purple{ \large :\longmapsto  \underline {\boxed{{\bf v =2 5 \: m/s} }}}$

Therefore,

$\large\underline{\pink{\underline{\frak{\pmb{\text Final \:  \text Velocit\text y = 25\: m/s }}}}}$

Answer 2

Given : A train starts from rest and accelerate uniformly at the rate of 5m/second square for 5 seconds then calculate the velocity of the train

Question states that a body is in rest and then accelerates uniformly at 5m/sec for 5 seconds after which the final velocity of the train needs to be calculated

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Given Data :

Initial Velocity (u) = 0 m/sec

Acceleration (a) = 5 m/sec

Time (t) = 5 sec

Calculation Begins :

For getting the solution of the question we need to apply the first equation of motion. Here only the the first equation is applicable because the other two has distance (S) which we are not provided according

❍ First Equation : v = u + at

Here, v represents the final velocity

Putting all the values we get

• v = 0 + 5(5)

• v = 0 + 25

• v = 25

Henceforth, the final velocity (v) is 25 m/sec

Learn More :

❍ Second Equation of Motion : S = ut + ½at²

❍ Third Equation of Motion : v² = u² - 2aS