Question

A train starts from rest and accelerate uniformly for 5 min. If it attains a velocity of 90 km. per hour, find its acceleration

Answer 1

Given :-

Time taken by the train = 5 min

Initial velocity of the train = 0 m/s

Final velocity of the train = 90 km/h

To Find :-

The acceleration of the train.

Analysis :-

Here we are given with the initial velocity, final velocity and the time taken by the train.

Using the first equation of motion substitute the values given in the question accordingly and find the acceleration.

Solution :-

We know that,

• v = Final velocity
• t = Time
• a = Acceleration
• u = Initial velocity

Using the formula,

$\underline{\boxed{\sf First \ equation \ of \ motion=v=u+at}}$

Given that,

Final velocity (v) = 90 km/h = 90000 m/s

Initial velocity (u) = 0 m/s

Time (t) = 5 min = 300 sec

Substituting their values,

⇒ 90000 = 0 + a × 300

⇒ a = (v-u)/t

⇒ a = (90000 - 0)/300

⇒ a = 90000/300

⇒ a = 900/3

⇒ a = 300 m/s

Therefore, the acceleration of the train is 300 m/s.

Answer 2

Answer:

Given :-

• A train starts from rest and accelerate uniformly for 5 minutes and its attains a velocity of 90 km/h.

To Find :-

• What is the acceleration.

Formula Used :-

★ a = v - u/t ★

where,

• a = Acceleration
• v = Final velocity
• u = Initial velocity
• t = Time

Solution :-

Given :-

➙ Final velocity = 90 km/s = 90000 m/s

➙ Initial velocity = 0 m/s

➙ Time = 5 minutes = 5 × 60 = 300 seconds

According to the question by using the formula we get,

⇒ a = 90000 - 0/300

⇒ a = 90000/300

⇒ a = 900/3

➠ a = 300 m/s²

∴ The acceleration of a train is 300 m/s² .