A train starts from rest and accelerates uniformly at 10 M per second square for 1 minutes find the velocity and the distance travelled by the train
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Vaishnavipandey15:
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U=0m/s;A=10m/s^2;T=60s;V=?;S=?
first eqution
v=u+at
v=0+10×60
v=600m/s
third equation
s=v^2+u^2/2a
s=600^2+0^2/2×10
s=360000÷20
s=18000m
first eqution
v=u+at
v=0+10×60
v=600m/s
third equation
s=v^2+u^2/2a
s=600^2+0^2/2×10
s=360000÷20
s=18000m
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