Question

A train starts from rest and accelerates uniformly at 10 ms-2 for 1 minutes find the velocity and distance travelled by the train atvthe end of 1 minutes

Answer 1

v = u + at
= (0 m/s) + (10 m/s² × 1 min × 60 s/min)
= 600 m/s
Velocity of train at the end of 1 minute is 600 m/s

S = ut + 0.5at²
= 0 + [0.5 × 10 m/s² × (60 s)²]
= 18000 m
= 18 km
Distance travelled by train at the end of 1 minute is 18 km

Answer 2

Answer: The distance travelled by train, at the end of 1 minute, is 18 km.

Explanation: According to the question,

As we know,

A train starts from rest and accelerates uniformly at 10 ms-2 for 1 minute.

The velocity and distance traveled by train at the end of 1 minute.

As we know, v=u+at is the first equation of motion.

Where,

u is the initial velocity

v is the final velocity

a is acceleration

t is the time period

v = u + at

  =(0m/s)+($10 m/s^2$ × 1 min × 60 s/min)

  =600 m/s

So now the velocity of the train at the end of 1 minute is 600 m/s

S = ut + 0.5at²

  =0+[0.5×10 m/s²×(60 s)²]

  =18000 m

  =18 km

As the distance traveled by train, at the end of 1 minute is 18 km.

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