A train starts from rest and accelerates uniformly for 30 seconds to acquire a Velocity of 108 km/h. It travels with this velocity for 20 minutes. The driver now applies brakes and the train slows down uniformly to stop after 20 seconds. Find the total distance covered by the train.
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0
Answer:
30 minutes
Explanation:
a train starts from rest and acceletrates uniformly for 30 seconds to acquire a velocity of 108 km/h.
Answered by
1
V = 108km/hr = 30m/s
t1 = 30 second
t2 = 20min = 1200sec
t3 = 20 second
Now, Lets divide the distance in 3 parts
First is distance for accelerating part
2nd is distance for constant velocity part
3rd is distance for retardating part
For first part
v= u + at
30 = 0+ a×30
a = 1m/s^2
2×a× S1 = V^2 - U^2
2×1 × S1 = 30^2 -0
S1 = 450m
For 2nd part
S2 = ut
= 30× 1200= 36000m
For 3rd part
V= u + at
0 = 30+ a×20
a = -30/20 = -1.5
2× a × S3 = V^2 - U^2
2(-1.5) × S3 = 0 - 30^2
S3 = 900/3 = 300m
S = S1+S2+S3
= 450+36000+300 = 36850m
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