Question

a train starts from rest and attains a speed of 54km/h in 10 sec calculate -
a. the acceleration
b. distance covered by the train.

Answer 1

The initial velocity of train is given u=0

v=54kmph=15m/s

so by the equation...
v=u + at
15=0 +10a
or a=1.5m/s

Now by equation

v^2=u^2+2as
15^2=0+2(1.5)s
225=3s
s=225/3=75m