Question

a train starts from rest and for the first one kilometer it has a constant velocity and for another 2 kilometer it moves with constant retardiation to come to rest after a total time of 10m. then maximum velocity of the train is​

Answer 1

and from equation 1

t1=1/v1

so putting all values =>2=(1/6-1/v1)*1/2.V1

solving it

V1=30km/hr(max speed)

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