Question

A train starts from rest and gains a velocity of 36 km per hour in 6 minutes find acceleration
Find the distance in km

Answer 1

Answer:

velocity= 36

time = 6 min

a= v-u/t

v= 36,u=0

a= 36-0/0.6

a =60km/sec

distance

$s = ut + 1 \div 2at {}^{2}$

s= 1/2×60×0.36

10.8 km

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Answer 2

Answer:

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Explanation:

u=0

v=36×1000=3600

t=6mins=6×60=360sec

acceleration =v-u/t

3600-0/360

=10m/sec²

s=u×t+1/2at²

=0+1/2(10)(360)²

=(5)(129600)

=648000 m

m to Km will be divided by 1000

648000/1000

=648km