A train starts from rest attains a velocity of 18km/h in 3minutes find acceleration
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Answered by
1
initial velocity [u] of the car = 0 km/h
final velocity [v] of the car = 18 km/h
time taken [t] = 3 min. = 3/60 h
v = u + at
⇒ a = v-u/t
⇒18-0 = a × 1/20
⇒18×20 = a
⇒a = 360 km/h² = 1296 m/s²
final velocity [v] of the car = 18 km/h
time taken [t] = 3 min. = 3/60 h
v = u + at
⇒ a = v-u/t
⇒18-0 = a × 1/20
⇒18×20 = a
⇒a = 360 km/h² = 1296 m/s²
Answered by
0
initial velocity of train =0m/s
final velocity =18 km/h
converting 18 km/h into m/s
18*5/18
=5m/s
time =3min
converting min into sec
3*60=180sec
acceleration= final velocity - initial velocity/time taken
5-0/180
=1/36m/s^2
final velocity =18 km/h
converting 18 km/h into m/s
18*5/18
=5m/s
time =3min
converting min into sec
3*60=180sec
acceleration= final velocity - initial velocity/time taken
5-0/180
=1/36m/s^2
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