Question

a train starts from rest attains a velocity of 90 km per hour in 3 minute assuming that acceleration is uniform find acceleration and distance .​

Answer 1

Here, u ( initial velocity ) = 0

v ( Final Velocity ) = 90 km/h

t ( time taken ) = 3 min

First, bring all units same.

3 min = 3 × 60 s = 180 s

90 km/h = 90 × 5/18 = 25 m/s

v = u + at

25 = 0 + a(180)

25/180 = a

0.14 m/s² = a

s = ut + 1/2 ( at² )

s = (0)(180) + 1/2 (0.14)(180)(180)

s = (0.14)(90)(180)

s = 2268 m

ʜᴇɴᴄᴇ, (ɪ) 0.14 ᴍ/s² ᴀɴᴅ (ɪɪ) 2268 ᴍ

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Answer 2

Answer:

Here, u (initial velocity) = 0

v (Final Velocity ) = 90 km/h

t ( time taken ) = 3 min

41

:

First, bring all units same.

3 min = 3 × 60 s = 180 s

90 km/h = 90 × 5/18 = 25 m/s

v = u + at

25 = 0 + a(180)

25/180 = a

0.14 m/s² = a

s = ut + 1/2 (at²)

s = (0)(180) + 1/2 (0.14)(180)(180)

s = (0.14)(90)(180)

s = 2268 m

HENCE, (I) 0.14 M/S² AND (II) 2268 M

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