Question

A train starts from rest from a station with acceleration 0.2 metre per second square on a straight track and then comes to rest after attending maximum speed on another station to retardation 0.4 metre per second square if total time spent in half an hour then distance between two station is

Answer 1

Answer:

In first case, u=0,a=0.2,let time=t, S(1)=ut+1/2at^2, v=u+at. In sacond case, u=v a=-0. 4 time=30-t, S(2)=ut+1/2at^2.

Therefore, the Totaldistance=s(1)+s(2). Due to retardation, the total time spent is half an hour and distance could be evaluated.

This should be obtained and includes another station due to retardation and consider 0.4m/s.

Within average time, it comes to rest after attending acceleration and then comes to rest after it.