Question

A train starts from rest from a station with acceleration 0.2 m/s2 on a straight track and then comes to rest after attaining maximum speed on another station due to retardation 0.4m/s2 .if the total time taken was half an hour then distance between two stations is

Answer 1

Explanation:

Given,

If A is the acceleration of the train and B is the retardation of the train , then the total distance travelled is given by [(AB)/(A+B)].(T^2/2

Here A = 0.2m/s^2 and B = 0.4m/s^2 and T = 1/2 hr = 1800 sec

Therefore x=[ (0.2)(0.4)/0.2+0.4)]x1800x1800/2 = 216000m = 216km

Hence the correct answer is 216km

hope you can understand.....