A train starts from rest gains an uniform acceleration attains speed 40 km\h in 10 min .Find its acceleration
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Explanation:
speed=40km/h
time=10min=10/36h
distance=?
distance=speed×time
distance=40×10/36
=400/36
=11.1km
acceleration,a=?
initial velocity,u=0
time,t=10
distance,s=11.1×1000=1100
we have second equation of motion
s=ut+1/2at²
1100=0×10+1/2×a×(10)²
1100=0+1/2×a×100
1100=100a/2
a=1100×2/100
a=2200/100
a=1100m/s²
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