A train starts from rest. it acquires a speed of 25 ms−1 after 20 s. total distance is
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s=ut+at ^2
0×20+25×20^2
0+25×400
10000m/s
0×20+25×20^2
0+25×400
10000m/s
Answered by
0
Answer:
total distance covered by train is 250 m.
Explanation:
Given:
initial velocity u=0 ms−1
final velocity v = 25 ms−1
time t =20s
Let acceleration of train be a , distance travelled s.
Here we do not have the value of acceleration. We will calculate that using,
a= v −u / t
= 25−0 /20
= 1.25 ms−2
Now using, third equation of motion,
v^2− u^2 =2as
( 25)^2 − (0)^2 = 2×1.25×s
625 /2.50. = s
s = 250 m
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