Question

A train starts from rest. it acquires a speed of 25 ms−1 after 20 s. total distance is

Answer 1

s=ut+at ^2
0×20+25×20^2
0+25×400
10000m/s

Answer 2

Answer:

total distance covered by train is 250 m.

Explanation:

Given:

initial velocity u=0 ms−1

final velocity v = 25 ms−1

time t =20s

Let acceleration of train be a , distance travelled s.

Here we do not have the value of acceleration. We will calculate that using,

a= v −u / t

= 25−0 /20

= 1.25 ms−2

Now using, third equation of motion,

v^2− u^2 =2as

( 25)^2 − (0)^2 = 2×1.25×s

625 /2.50. = s

s = 250 m

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