Question

A train starts from rest. It acquires a speed of 25m/s after 20 seconds. The total distance is...

Answer 1

Answer:

250 metres

Explanation:

Given :

• Initial velocity = u = 0 m/s

• Final velocity = v = 25 m/s

• Time taken = t = 20 seconds

To find :

• Distance travelled by the train

Acceleration = (v-u) / t

Acceleration = (25-0)/20

Acceleration = 25/20 = 1.25 m/s²

Using the third equation of motion :

V²-u²=2as

25²-0²=2×1.25×s

625=2.5s

s = 625/2.5

S = 250 metres

The distance travelled by the train is equal to 250 metres

Answer 2

✯✯ QUESTION ✯✯

A train starts from rest. It acquires a speed of 25m/s after 20 seconds. The total distance is...

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✰✰ ANSWER ✰✰

$\implies\tt{Initial\:Velovity(u)=0m/s}$

$\implies\tt{Final\:Velocity(v)=25m/s}$

$\implies\tt{Time\:Taken(t)=20\:sec}$

$\implies\tt{Distance(s)=?}$

➮Firstly we will find the acceleration : -

➥Using 1st Equation : -

$\implies\tt{\small{\boxed{\bold{\bold{\red{\sf{v=u+at}}}}}}}$

➥Putting Values : -

$\implies\tt{25=0+a(20)}$

$\implies\tt{25=20a}$

$\implies\tt{a=\cancel\dfrac{25}{20}}$

$\green\longmapsto\:\large\underline{\boxed{\bf\pink{a}\orange{=}\blue{1.25{m/s}^{2}}}}$

☛So , The acceleration is 1.25m/s²..

➥Using 2nd Equation : -

$\implies\tt{\small{\boxed{\bold{\bold{\orange{\sf{s=ut+\dfrac{1}{2}{at}^{2}}}}}}}}$

➥Putting Values : -

$\implies\tt{s=(0)(20)+\dfrac{1}{2}\times{1.25}\times{20}\times{20}}$

$\implies\tt{s=\dfrac{1}{2}\times\dfrac{125}{100}\times{20}\times{20}}$

$\implies\tt{s=\cancel\dfrac{5000}{200}}$

$\red\longmapsto\:\large\underline{\boxed{\bf\green{s}\orange{=}\purple{250\:m}}}$

☛So , Distance travelled by the train is 250 m....