Question

A train starts from rest. It moves through 1 Km in 100 s with uniform acceleration.
What will be its speed at the end of 100 s.


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Answer 1

Answer:

56

Explanation:

$y { = < = y { |7(| }^{2} }^{?}$

Answer 2

Explanation:

Using the equations of motion,

s = ut+1/2 at^2

v = u + at,

where

s = displacement,

u = initial velocity

a = acceleration

t = time

Using the first equation s = ut+1/2 at^2

1ooom = 0(t) +1/2(a)(100s)^2

Solving for a, we obtain:

a = 0.2m/s^2

Using the other equation of motion:

v = u + at,

v = 0 + (0.2m/s^2)(100s)

v = 20m/s

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