Question

A train starts from rest. It moves through 1 Km in 100S with uniform acceleration.What will be its speed at end of 100S?

Answer 1

Answer:

10m/s

Step-by-step explanation:

speed=1000m/100s

=10m/s

Answer 2

$\Large{\textbf{\underline{\underline{According\:to\:the\:Question}}}}$

Initial velocity(vi)

= 0 m/s

s = 1 km

$\textbf{\underline{Convert\;it\;into\;m}}$

s = 1000 m

t = 100 sec

$\textbf{\underline{To\;find:- }}$

Acceleration = ?

Final velocity(vf) = ?

${\boxed{\sf\:{Using\;Formula:-}}}$

$\tt{\rightarrow s=vit+\dfrac{1}{2}\times at^2}$

$\tt{\rightarrow 1000=(0)(100)+\dfrac{1}{2}\times a(100)^2}$

$\tt{\rightarrow 1000=0+\dfrac{1}{2}\times a(100)^2}$

$\tt{\rightarrow 1000=0+\dfrac{1}{2}\times a(10000)}$

1000 = a × 5000

$\tt{\rightarrow a=\dfrac{5000}{1000}}$

$\tt{\rightarrow a=0.2\; ms^{-1}}$

Now,

vf = vi + at

vf = 0 + (0.2) × 100

$\tt{\rightarrow vf=20\;ms^{-1}}$