Question

a train starts from rest it moves through 1 km in 100s with uniform acceleration what eill be its speed at end of 100 s​

Answer 1

Answer:

Initial velocity(vi)

= 0 m/s

s = 1 km

\textbf{\underline{Convert\;it\;into\;m}}

Convertitintom

s = 1000 m

t = 100 sec

\textbf{\underline{To\;find:- }}

Tofind:-

Acceleration = ?

Final velocity(vf) = ?

{\boxed{\sf\:{Using\;Formula:-}}}

UsingFormula:−

\tt{\rightarrow s=vit+\dfrac{1}{2}\times at^2}→s=vit+

2

1

×at

2

\tt{\rightarrow 1000=(0)(100)+\dfrac{1}{2}\times a(100)^2}→1000=(0)(100)+

2

1

×a(100)

2

\tt{\rightarrow 1000=0+\dfrac{1}{2}\times a(100)^2}→1000=0+

2

1

×a(100)

2

\tt{\rightarrow 1000=0+\dfrac{1}{2}\times a(10000)}→1000=0+

2

1

×a(10000)

1000 = a × 5000

\tt{\rightarrow a=\dfrac{5000}{1000}}→a=

1000

5000

\tt{\rightarrow a=0.2\; ms^{-1}}→a=0.2ms

−1

Now,

vf = vi + at

vf = 0 + (0.2) × 100

\tt{\rightarrow vf=20\;ms^{-1}}→vf=20ms

−1