Question

A train starts from rest with an
acceleration of 0.5 ms -1. Find its
speed in kmh-1, when it has
moved through 100 m.
​

Answer 1

Answer:

36 km/hr

Explanation:

We will use 3rd equation of motion:

v^2-u^2=2as

Given : u (initial velocity )=0

a = 0.5m/s

s(distance) = 100m

Put the values and find v:

v^2-0 = 2*0.5*100

v^2 = 100+0

v^2= 100

v = √100

= 10m/s

Convert the value in km/hr:

10*18/5

= 36km/hr.

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