Question

A train starts from rest with an acceleration of 0.5 ms 2. Find its speed in kmh, when it has moved through 100 m.​

Answer 1

36km/hr

Explanation:

since the acceleration of the train was 0.5m/s² i.e it is constant . since the acceleration is constant you can use one of the “SUVAT” equations to find the answer.

the equation that best fits this question is: v² = u² + 2āS.

v stands for final velocity

u stands for intial velocity

v² = u² + 2āS since the car started from rest the intial velocity is zero.

v² = u² + 2āS

v² = 0 + 2(0.5m/s²) x 100m

v² = 1m/s² x 100m

√v² = √100m²/s²

v = 10m/s

1km/hr = 1/3.6m/s

x. = 10m/s.

use criss cross method to find the value of x

x = ( 1km/hr x 10m/s)

1/3.6m/s

x = 36km/hr