Question

a train starts from rest with uniform acceleeation and attains a speed of 90km/hr in 100 sec. Determine the acceleration of the train​

Answer 1

Answer :-

0.9m/s^2

Explanation :-

Given :

Initial velocity of the train,u => 0m/s

Final velocity of the train,v => 90m/s

Time taken,t => 100s

To Find :

Acceleration,a = ?

Solution :

According to the first law of equation,

$\sf{}v=u+at$

Put their values and find a

$\sf{}\implies 90m/s=0m/s+a\times 100s$

$\sf{}\implies 90m/s=a\times 100s$

$\sf{}\implies \dfrac{90m/s}{100s}=a$

$\sf{}\implies a= 0.9m/s^2$

☆Know more☆

Equation of motion :- Relation among velocity,distance,time and acceleration is called equation of motion.

There are three equation of motion,

$\sf{}First\ equation\ motion:\ v=u+at$

$\sf{}Second\ equation\ motion:\ s=ut+\dfrac{1}{2}at^2$

$\sf{}Third\ law\ motion:\ v^2=u^2+2ast$

Answer 2

Given

• Initial velocity (u) = 0 m/s

• Final velocity (v) = 90 km/hr = 25 m/s

• Time (t) = 100 seconds

_____________________...

Answer:

$\bigstar \: \boxed{\boxed{\sf Acceleration = \dfrac{Change \: in \: velocity}{Time \: taken}}} \: \bigstar$

$:\implies\sf Acceleration = \dfrac{Final \: velocity - Initial \: velocity}{Time \: taken}$

$:\implies\sf a = \dfrac{v - u}{t}$

$:\implies\sf Acceleration = \dfrac{25 - 0}{100}$

$:\implies \underline{ \boxed{\sf Acceleration = 0.25 \: m/s^{2} }}$

$\therefore\:\underline{\sf{Acceleration \: produced \: is \: 0.25 \: m/s^{2}}}.$