A train starts from station A , accelerates uniformly at rate of 1.5m/s2 maximum speed in 20s .it then continues to move at this speed of 10min and then retards uniformly to rest at the station B after 30s .. Calculate maximum speed , retardation and distance between. Station A and B
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v=at since u=0
implies v=1.5*20=30m/s
max speed =30m/s
s1=1/2at^2
s1=0.5*1.5*400
s1=300
s2=vt
s2=30*10*60
s2=18000
retardation=u/t
r=30/30=1m/s^2
s3=1/2rt^2
s3=0.5*1*900
s3=450m
total d=450+18000+300
d=18.75km
implies v=1.5*20=30m/s
max speed =30m/s
s1=1/2at^2
s1=0.5*1.5*400
s1=300
s2=vt
s2=30*10*60
s2=18000
retardation=u/t
r=30/30=1m/s^2
s3=1/2rt^2
s3=0.5*1*900
s3=450m
total d=450+18000+300
d=18.75km
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