a train starts from station A and passes through station B , C , to finally reach at D , if station is 50 km from each other and takes 30 min to cover the distance and a break of 2 min at each station , what is average speed of train
Answers
average speed of train would be 88.23 km/h
It is given that a train starts from station A and passes through station B , C , to finally reach at D , if station is 50 km from each other and takes 30 min to cover the distance and a break of 2 min at each station
we have to find average speed of train.
average speed of train = (total distance covered by train)/total time taken
= (AB + BC + CD)/{t_A + t_(AB) + t_B + t_(BC) + t_C + t_CD + t_D}
= (50km + 50km + 50km)/(2min + 30min + 2min + 30min + 2min + 30min + 2min)
= 150km/(102 min)
= 150 km/(102/60 h)
= 88.23 km/h
hence average speed of train would be 88.23 km/h
Answer:
Explanation:
average speed of train = (total distance covered by train)/total time taken
= (AB + BC + CD)/{t_A + t_(AB) + t_B + t_(BC) + t_C + t_CD + t_D}
= (50km + 50km + 50km)/(2min + 30min + 2min + 30min + 2min + 30min + 2min)
= 150km/(102 min)
= 150 km/(102/60 h)
= 88.23 km/h