Question

A train starts from station A at 1pm and reaches station B at 3 pm, after travelling 108 km. It halts at station B for one hour and then starts for station which is 42 km from station B. It reaches station Cat 7 pm on the same day, The average speed of the train for the whole Journey from A to Cis

Answer 1

Answer:

30 km/ hrs

Explanation:

Average speed= Total distance ÷ total time of travel = (108km+42km)÷(2hrs+3hrs) = 150÷5=30

Answer 2

Answer:

average speed =total distance÷total time

so 1pm to 7 pm = 6hrs

and distance= 108+42

150÷6 = 25km/hrs