Question

a train starts from station and moves with a constant acceleration for 2 minutes if it cover a distance of 400 m in this period find its acceleration​

Answer 1

Answer

a = 0.055 m/$s^{2}$

Step-by-step explanation:

time(t) = 2min= 120 sec

distance(s) = 400m

initial velocity(u) = 0

we have

$s = (u*t) + (\frac{1}{2}* a*t^{2} )$

400= (0*120) + ( 0.5*a*(120*120))

acceleration (a) = 0.055 m/$s^{2}$