A train starts from station and moves with constant acceleration for 2min. if it covers a distance of400m in this period, find the acceleration
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As we know that
S=UT+1/2 AT²
400m = 0×0+1/2 A (120)² sec
400=A×120×60
A=400/120×60
A=0.055555556 m/s²
S=UT+1/2 AT²
400m = 0×0+1/2 A (120)² sec
400=A×120×60
A=400/120×60
A=0.055555556 m/s²
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