Question

A train starts from station x at the rate of 60 kmph and reaches station y in 45 minutes.If the speed is reduced by 6kmph,how much more time will the train take to return from station y to station x?

Answer 1

Given : The Train starts from Station X at the Rate of 60 kmph and Reaches Station Y in 45 Minutes.

Let us Calculate the Distance between Station X and Station Y

$\bold{We\;know\;that\;:45\;Minutes = \frac{45}{60} = \frac{3}{4}\;Hour}$

$\bold{We\;also\;know\;that\;:Distance = (Speed \times Time)}$

$\bold{\implies Distance\;between\;Station\;X\;and\;Station\;Y\; = (60)(\frac{3}{4}) = 45\;km}$

During the Return Journey from Station Y to Station X, The Speed of the Train was Reduced by 6 kmph.

⇒ Speed of the Train during the Return Journey = (60 - 6) = 54 kmph

$\bold{\implies Time = \frac{Distance}{Speed}}$

$\bold{\implies Time = \frac{45}{54} = \frac{5}{6} = 50\;Minutes}$

The Train takes 5 Minutes more to return from Station Y to Station X

Answer 2

Answer:

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