Question

a train starts from the rest and accelerated uniformly for 30 second to attend a velocity of 72 km per hour find its acceleration second distance travelled​

Answer 1

Step-by-step explanation:

Given

u = 0m/s

t = 30 second

v = 72km/hr = 72 × 5/18m/s = 20m/s

So a = (v - u)/t

a = 20-0/30

a = 2/3 m/s²

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Answer 2

Answer:

2/3m/s^2

Step-by-step explanation:

a=v-u/t

v=20

u=0

t=30