Question

A train starts full of passengers. at the first station, the train drops one-third of the passengers and takes in 96 more. at the next station, one half of the passengers on board get down while 12 new passengers get on board. the number of passengers now was 240. the number of passengers in the beginning was:​

Answer 1

Answer:

$\huge\underline\bold {Answer:}$

Let the full number passengers be x.

Number of passengers at the first station

$= (x - \frac{1}{3x} ) + 96 = \frac{2x}{3} + 96$

Number of passengers at the second station =

$\frac{1}{2} ( \frac{2x}{3} + 96) + 12 \\ = \frac{x}{3} + 48 + 12 = \frac{x}{3} + 60$

Given,

$\frac{x}{3} + 60 = 240 \\ = > \frac{x}{3} = 240 - 60 = 180$

$= > x = 180 \times 3 = 540.$

Therefore, the number of passengers in the beginning was 540.

Answer 2

Answer:

Step-by-step explanation:

I think it is a psychological question then also I will try my best to answer -

See

Let the full number of passengers be x

Number of passengers at the first station , after drops one-third of the passenger

=(x−

3

1

​

x)+96=

3

2x

​

+96

Number of passengers at the second station , after one-half get down and 12 added

=

2

1

​

(

3

2x

​

+96)+12=

3

x

​

+48+12=

3

x

​

+60

Given

3

x

​

+60=240⇒

3

x

​

=240−60=180

⇒x=180×3=540