Question

A train starts moving from rest and acquires a velocity of 72 km/h in 5 minutes. If the train moves at
a constant acceleration, calculate the following-
(1) Acceleration
(2)Distance travelled by the bus to acquire this velocity.​

Answer 1

Answer:

a = $\frac{v + u}{t}$

72 $\frac{km}{hr}$ = 20$\frac{m}{sec}$

5 mins = 300 secs

a = $\frac{20 - 0}{300}$

a = $\frac{2}{30} \frac{m}{sec^{2} }$

a = 0.0666666666....................