Question

a train starts moving from rest obtain velocity of 72 km\h in 5 minute asuming that the accleration is uniform , find out accleration & the distance travelled by the train for obtaining this velocity​

Answer 1

Answer:

Step-by-step explanation:

STARTS FROM REST IMPLIES:

INITIAL VELOCITY , U = 0 M/S

FINAL VELOCITY , V = 72 KM/H   TO CONVERT KM/H TO M/S * BY 5/18

                                  = 72*5/18     TO CONVERT M/S TO KM /H * BY 18/5

                                   = 20 M/S

TIME TAKEN , T= 5 MIN

                         = 5*60

                          = 300 SEC

ACCELERATION, A=?

DISTANCE TRAVELLED , S=?

USING NEWTON'S FIRST LAWS OF MOTION:

V = U+A T

20 = 0+A*300

A = 20/300

A = 2/30

A = 0.06 M/S²

USING SECOND LAW OF MOTION

S = U T+1/2 AT²

S = 0*300+1/2*0.06*300*300

S = 0+150*300*0.06

S = 2,700 M

S = 2.7 KM.

HOPE THIS HELPS.

Answer 2

Answer:

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