Question

A train starts to move from rest. After 5 minutes, its velocity becomes 25m/s. What is its acceleration​

Answer 1

⚘ Given That :

• ➻ Initial Velocity of Train (u) = 0m/s
• ➻ Final Velocity of Train (v) = 25m/s
• ➻ Time Taken by Train (T) = 5 Min

⚘ Need To Find :

• ➮ The acceleration of Train ?

⌬ Formula Used Here :

• ✪ a = v - u / t ✪

✧ Where :

• ↣ a = Acceleration
• ↣ v = Final Velocity
• ↣ u = Initial Velocity
• ↣ t = Time

____________________

☢ Conversion Needed :

◆ Time taken by train 5 min into seconds :

• ⇢ Time = 5 × 1min
• ⇢ Time = 5 × 60 s
• ⇢ Time = 300s

✇ Putting Values in Formula :

• ➟ a = v - u / t
• ➟ a = ( 25 - 0 ) / 300s
• ➟ a = 25 / 300
• ➟ a = 0.0833m/s² [ Approximately ]

✠ Therefore :

» Acceleration of Train will be 0.0833 m/s²

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Answer 2

Information given to us:

• A train starts to move from rest
• After 5 minutes, its velocity becomes 25m/s

What we have to calculate:

• Acceleration caused?

Formula used:

• Acceleration = Final velocity - Intial velocity / Time

Converting minutes into seconds:

• As we have 5 minutes inorder to convert it into it into seconds we have to multiply 5 with 60 because one minute contains 60 seconds.

=> T = 5 × 60

=> T = 300 seconds

Evaluating the values in the given formula of calculating the acceleration:

Here we have,

• v is 25 m/s
• T is 300s
• u is 0

Lets solve it now!

=> a = 25 - 0 / 300

• On substracting 25 with 0 we gets 25,

=> a = 25 / 300

• Dividing 25 by 300,

=> a = 5 / 60

• Dividing 5 by 60,

=> a = 1 / 12

• Now we gets,

=> a = 0.083333

Conclusion:

• Acceleration is of 0.083333 m/s²

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