Question

a train starts travelling with a velocity of 72km/h breaks are applies so that its velocity decreases at a rate of 0.5m/s² find the did travelled by it before coming to rest​

Answer 1

Answer:

400 metres

Explanation:

Given :

• Initial velocity = u = 72 km/hr = 72×5/18 = 20 m/s

• Final velocity = v = 0 m/s

• Acceleration = a = -0.5 m/s²

To find :

• Distance travelled by train

Using the third equation of motion :

V²-u²=2as

0²-20²=2×-0.5×s

0-400=-1s

-400=-1s

S=400 metres

The distance travelled by the train is equal to 400 metres or 0.4 km

More :

• First equation of motion = v=u+at
• Second equation of motion = s=ut+½at²

Answer 2

..It's helps u dear..

nice day