Question

a train starts with the velocity of 36 km/h and attains the velocity of 54 km/h in 1/2 minute with uniform acceleration. what will be its acceleration?
Please answer In m/s^2. ​

Answer 1

Explanation:

v=u+at

a=(v-u)/t -----------(1)

v=72 km/h

=20m/s

u=0

t=5*60 sec =300sec

by putting values of v,u,t in (1)

a=1/15 m/s2

s=ut +(1/2)at2

=0+(1/2)(1/15)(300)(300)

=3km

Answer 2

Answer:

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Explanation:

Expert Answer:

As the train starts from rest, u = 0

v = 40 km/ h =11 m/s

t =10 min = 10 × 60 = 600 s

By first equation of motion,

v = u + at

11 = 0 + a (600)

Thus,

a = 11/600 = 0.018 m/s2