A train stating from a railway station and moving with uniform acceleration at the speed 40 km/hr in 10 minutes find its acceleration
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u=0 m/s
v=40 km/hr =(40×5/18)m/s=11.11 m/s
t=10 min=(10×60)sec=600sec
a=(v-u)/t
a=(11.11-0)/600
a=11.11/600
a=0.0185m/s^2
answer- acceleration is 0.0185 m/s^2
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v=40 km/hr =(40×5/18)m/s=11.11 m/s
t=10 min=(10×60)sec=600sec
a=(v-u)/t
a=(11.11-0)/600
a=11.11/600
a=0.0185m/s^2
answer- acceleration is 0.0185 m/s^2
PLZ MARK MY ANSWER AS BRAINLIEST
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