Question

A train stationary position
and moving with Uniform
acceleration attains a speed of
36 km ber hour in 10 minutes
and its acceleration?​

Answer 1

Explanation:

u = 0

v = 36 kmph = 36 x 5/18 = 10m/s

t = 600 s

a = v-u / t

a = 10 - 0 / 600

a = 1/60 = 0.0167 m/s²