Question

A train statring position and moving with uniform acceleration attains a speed of 36km/hr in 10 mins. Find acceleration

Answer 1

well, the final velocity given is 36km/hr

In SI unit the velocity (v) = 36*1000/3600 m/s

hence, v = 10m/s

Now, time (t) = 10min = 600 second

We know acceleration =change in velocity/time

as initial velocity is 0. u=0

and hence, a = v/t

a = 10/600

a = 0.01667 m/s square

Answer 2

Given:-

• Initial velocity of train, u = 0
• Final velocity of train v = 36 km/h.
• Time taken, t = 10 minutes

To Find:-

• What is the acceleration of train ?

Solution:

• Firstly we have to change the final velocity from km/h to m/s and also time to seconds. To change km/h to m/s multiply by 5/18. We are given :-

• Final velocity, v = 36 × (5/18) = 10 m/s.

➟(1 minutes = 60 seconds)

• Now we know first equation of motion is given by :-
• v = u + at

Substituting the values :-

⇢10 = 0 + a × 600

⇢10 = 600a

⇢a = 10/600

⇢a = 0.0166 m/s²

• Hence, the acceleration of train is 0.0166 m/s².