Question

a train stops with an acceleration of 6m/s² in 2 seconds . calculate distance cover by train.​

Answer 1

Answer:

Acceleration a = -6 m/s^2

Time t = 2 s

Final velocity v = 0 m/s

Let initial velocity be u Let distance be s

v=u+ at

So, 0 = u + (-6)(2)

So, u = 12 m/s

Now, s = ut + (1/2) at^2 So, s = 12(2) + (1/2)(-6)(2^2)

So, s = 24 - 12

So, s = 12 m

Thus, distance travelled is 12 m