a train take 18sec tp pass thourgh a platform 162m long and 15sec to pass thourgh another platform 120m long. the lenght of the train ( in m) is
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A train takes 18 seconds to pass through a platform 162 m long and 15 seconds to pass through another platform 120 m long then the length of the train is?
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K S Narayanan, former General Manager - Revenue Assurance at Aircel Limited (2007-2009)
Answered Feb 4
Simple question of TSD
Smart Method :
The train covers 162 - 120 = 42 m in 18 - 15 = 3 seconds.
=> Speed of train = 42/3 = 14 m/s
The train covers 18 x 14 = 252 m in 18 seconds.
=> Length of train = 252 - 162 = 90 m.
Traditional Method :
Let length of train = L
In first case, train covers 162 + L m in 18 seconds and in second case train covers 120 + L m in 15 seconds.
Speeds are (162 + L)/18 and (120 + L)/15 respectively.
But they are equal.
=> (162 + L)15 = (120 + L)18
=> 2430 - 2160 = 3L
=> L = 270/3 = 90 m
Answer
4
Follow
Request
More
5 ANSWERS

K S Narayanan, former General Manager - Revenue Assurance at Aircel Limited (2007-2009)
Answered Feb 4
Simple question of TSD
Smart Method :
The train covers 162 - 120 = 42 m in 18 - 15 = 3 seconds.
=> Speed of train = 42/3 = 14 m/s
The train covers 18 x 14 = 252 m in 18 seconds.
=> Length of train = 252 - 162 = 90 m.
Traditional Method :
Let length of train = L
In first case, train covers 162 + L m in 18 seconds and in second case train covers 120 + L m in 15 seconds.
Speeds are (162 + L)/18 and (120 + L)/15 respectively.
But they are equal.
=> (162 + L)15 = (120 + L)18
=> 2430 - 2160 = 3L
=> L = 270/3 = 90 m
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