A train takes 18 seconds to pass through a platform 162 m long and 15 seconds to pass through another platform 120 m long the length of train is in meters
Answers
Answered by
25
The train length is 90m.
Solution:
Assume L be the length of the train.
The train covers a distance of (162 + L) in 18 seconds.
The rate is then (162 + L)/18.
The train also covers a distance of (120 + L) in 15 seconds.
The rate is then (120 + L)/15.
Presumably, the train is traveling at a constant rate. Therefore, set the two rates equal to each other and solve for L.
(162 + L)/18 = (120 + L)/15
Cross multiply and solve for L
(162 + L) * 15 = (120 + L) * 18
2430 + 15L = 2160 + 18L
2430 - 2160 = 18L - 15L
270 = 3L
L = 270/3
L = 90m.
The length 90m.
Solution:
Assume L be the length of the train.
The train covers a distance of (162 + L) in 18 seconds.
The rate is then (162 + L)/18.
The train also covers a distance of (120 + L) in 15 seconds.
The rate is then (120 + L)/15.
Presumably, the train is traveling at a constant rate. Therefore, set the two rates equal to each other and solve for L.
(162 + L)/18 = (120 + L)/15
Cross multiply and solve for L
(162 + L) * 15 = (120 + L) * 18
2430 + 15L = 2160 + 18L
2430 - 2160 = 18L - 15L
270 = 3L
L = 270/3
L = 90m.
The length 90m.
Answered by
7
Answer:
90 m is the length
Step-by-step explanation:
refere to the attachment
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