Physics, asked by HRK007007, 2 months ago

a train takes 2 h to reach station B from station A, and
then 3 h to return from station B to station A. The
distance between the two stations is 200 km. Find :
(i) the average speed, (ii) the average velocity of the

Answers

Answered by ramakatiyar9
0

Answer:

the average velocity the

Answered by Eutuxia
4

Question :

A train takes 2 h to reach station B from station A, and then 3 h to return from station B to station A. The distance between the two stations is 200 km. Find : (i) the average speed, (ii) the average velocity of the train.

_______________________

Before, finding the answer. Let's find out how we can find the answer.

  • In this question, we are asked to find two things. One is to find the average speed of the Train and next to find the average velocity of the Train.
  • So, to find the Speed, we have to first add the time between two stations. Then, we have to add the distance between the two stations.
  • Next, to find the Average Speed, we have to use the formula of :

\boxed{ \sf Average \: Speed = \dfrac{Distance }{Time} }

  • Next, to find the Average Velocity, we have to use the formula of :

\boxed{ \sf Average \: Velocity = \dfrac{Displacement }{Time} }

____________________

Given :

  • Time to reach Station A to B = 2 hours
  • Time to reach Station B to A = 3 hours
  • Distance = 200 km

To find :

  • (i) the average speed
  • (ii) the average velocity of the

Solution :

⇒ Total Time = 2 + 3 hours

                  = 5 hours

⇒ Total Distance = 200 + 200 km

                        = 400 km

Now,

\Rightarrow { \sf Average \: Speed = \dfrac{Distance }{Time} }

                           { \sf   = \dfrac{400}{5} }

                           \sf = 80

  • Therefore, the Average speed of the Train is 80 km/hr.

⇒ Next, let's find out the Velocity of the Train.

  • And here, we are taking Displacement as 0 as the train has returned to its original place.

\Rightarrow { \sf Average \: Velocity = \dfrac{Displacement }{Time} }

                              \sf {= \dfrac{0}{5 }

                              \sf = 0

Therefore, the Average Velocity of the Train is 0.

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