A train takes 2 hours less for a journey of 300 kilometre if its speed is increase by 5 km/hr from its usual speed find the usual speed of train
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we know that
speed =distance/time
speed=300/2
speed =150km/hr
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0
Answer:
Let the usual speed of the train be y km / hr .
A.T.Q.
300 ( y + 5 ) - 300 y = 2 y ( y + 5 )
y² + 5 y - 750 = 0
y² + 30 y - 25 y - 750 = 0
( y + 30 ( y -25 ) = 0
y = - 30 or y = 25
Since , speed of train can't be negative .
Therefore , the usual speed of the train is 25 km / hr .
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