A train takes 2 hours less for a journey of 300 km,
its speed is increased by 5km/hr from its usual
speed. Find the usual speed of the train.
Answers
Answered by
3
Let n be the usual speed, and n+5 be the faster speed. Then:
300/n=300/n+5 +2
300(n+5)=300n+2n²+10n
2n²+10n-1500=0
n²+5n-750=0
(n+30)(n-25)=0
n=25 km/h
Answered by
0
Answer:
300/x minus 300/x+5=2
300(1/xminus1/x+5)=2
x square +5x minus 750=0
x square +30x minus 25x minus 750=0
X=25km/hr
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