A train takes 2 hours less for a journey of 300km. If
the speed is increased by 5km/hr from its usual
speed, find the usual speed of the train.
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Answer:
Let the usual speed of the train is x km/h.
D=300 km (Given)
Speed= time/distance
Time= 300/x
After increasing the speed of the train ;
New speed is (x+5) km/h
Time= 300/x+5
Now, difference between the time taken by usual speed and after increasing speed of the train is two hours. Therefore,
300/x-300/x+5=2
⇒300( 1/x-1/x+5) =2
x+5-x/x square+5x=2/300
5/x square +5x =1/150
⇒x square +5x−750=0
⇒x square +30x−25x−750=0
⇒x(x+30)−25(x+30)=0
⇒(x+30)(x−25)=0
⇒x=25,−30
Ignore the negative value of the speed.
Hence, the usual speed of the train is 25 km/hr.
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