A train takes 2hours less than a train Q for a journey of 480km. If the speed of a train Q is 20km/hr less than that of train P. find the speed of the trains P and Q.
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Step-by-step explanation:
480/x - 480/x-20=2
480(1/x -1/x-20)=2
480 (X -20 -x) =2x²-2x
480(20)=2x²-2x
9600=2x²-2x
2x²-2x-9600=0. /2
x²-x-4800=0
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