A train takes 3.5 hrs to reach station B from station A, and then 4.5 hrs to return from station B to station A. The distance between the 2 stations is 300km. Find the average speed and average velocity of the train?
Answers
Given that, the distance between two stations is 300 km.
Also given that, A train takes 3.5 hrs to reach station B from station A, and then 4.5 hrs to return from station B to station A.
As per given condition,
Distance from A to B station (A → B) = 300 km and Distance from B to A station (B → A) = 300 km
Therefore, the total distance = (A → B + B ← A) 300 + 300 = 600 km
Now,
a) Average Speed = (Total Distance)/(Total time)
Total time = (3.5 + 4.5)hrs = 8.0 hours or 8 hours
Substitute the known values
⇒ 600/8
⇒ 75 km/hr
b) Average Velocity = (Total displacement)/(Total time)
Now, as trains start from station A then reach station B, later return to station A again.
As it's starting and ending points or destinations are same. So, displacement is zero.
⇒ 0/8
⇒ 0 km/hr
.,....
QUESTION :
A train takes 3.5 hrs to reach station B from station A, and then 4.5 hrs to return from station B to station A.
The distance between the 2 stations is 300km.
Find the average speed and average velocity of the train?
SOLUTION :
From the above Question, we can get the following information...
A train takes 3.5 hrs to reach station B from station A, and then 4.5 hrs to return from station B to station A.
A train takes 3.5 hrs to reach station B from station A, and then 4.5 hrs to return from station B to station A. The distance between the 2 stations is 300km.
The distance between the two stations is 300 km.
So, distance = 300 km. × 2 = 600 km
Now, Total time taken to cover this distance :
Total time by: 3.5 hrs + 4.5 hrs = 8 hrs =
Now we know that :
Average Speed = Total distance covered / Total time taken.
So ,
Average Speed = 600 km / 8 hrs = 75 kmph.
Now, the Displacement of the train is 0 km as the train returns to the same point.
Average Velocity is equal to : Total Displacement / Time taken
=> 0 kmph.