Question

A train takes 3 h to reach station B from station A and then 4 h to return from station B to station A. The distance between the two stations is 300 km. Find (i) the average speed, (ii) the average velocity of the train.

Answer 1

Answer :-

Given :-

• Train takes 3 hours to reach station B from station A.
• It takes 4 hours to return from station B to station A.
• Distance between the two stations = 300 km

To Find :-

• Average speed
• Average velocity

Solution :-

We know that,

→ Average speed = Total distance / Total time

Here, the train moves from station A to station B and then again to station A. So,

→ Total distance covered by train = 300 + 300 = 600 km

→ Total time taken = 3 + 4 hours = 7 hours

Hence,

Average speed = 600 / 7 km/hr

→ Average velocity = Total Displacement / Total time

Here, the train has started from station A and then returned to station A. So, displacement of train is equal to zero.

Average velocity = 0

Answer 2

Answer:

(i) the average speed= 85.71km/hr

(ii) the average velocity of the train=0km/hr.

Explanation:

Given Information -

• Distance from A to B = 300km
• Time taken from A to B= 3 hours
• Time taken from B to A = 4 hours

To Find-

• (i) The Average Speed.
• (ii) The Average Velocity.

Answer-

(i) Average Speed-

Total time taken = 3+4= 7hours

Distance travelled from A to B= 300km

Distance travelled from B to A = 300km

Total distance travelled = 600km

Average Speed - $\bold{\frac{total\:distance}{total\:time}}$

• $\frac{600}{7}$

• $\bold\red{85.71km/hr}$

ㅤ

(ii) Average Velocity -

Initial position =A= 0km/hr

Final Position =A= 0km/hr

Velocity = 0km/hr

Average Velocity = $\bold\red{0km/hr}$