A train takes 4 h to travel from station A to station B and return to station B in 6 h.
distance between station A and station B is 800 km. Find the average speed of the train.
Answers
ㅤ
• Distance between station A and B
( d₁ or d₂) = 800km
• Time taken to go= 4 hr
• Time taken to back = 6 hr
ㅤ
• Average speed of the train
ㅤ
ㅤ
━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━
Explanation:
ㅤGiven:-‾\;\;\underline{\textbf{\textsf{Given:-}}}
Given:-
• Distance between station A and B
( d₁ or d₂) = 800km
• Time taken to go= 4 hr
• Time taken to back = 6 hr
ㅤTo Find :-‾\;\;\underline{\textbf{\textsf{To Find :-}}}
To Find :-
• Average speed of the train
ㅤSolution :-‾\;\;\underline{\textbf{\textsf{Solution :-}}}
Solution :-
As we know that :‾\underline{\:\textsf{ As we know that :}}
As we know that :
Average speed=Total DistanceTotal time\boxed{\sf \ Average \ speed = \dfrac{Total \ Distance}{Total \ time }}
Average speed=
Total time
Total Distance
Putting the values :‾\underline{\:\textsf{Putting the values :}}
Putting the values :
⇢Average speed=d1+d2t1+t2⇢Av. speed=800+8006+4⇢ Av. speed=160010⇢ Av. speed=160km/h\begin{lgathered}\dashrightarrow \sf Average \ speed = \dfrac{d_1+d_2}{t_1+t_2}\\ \\ \dashrightarrow \sf Av.\ speed = \dfrac{800+800}{6+4}\\ \\ \dashrightarrow \sf \ Av.\ speed = \dfrac{1600}{10}\\ \\\dashrightarrow \sf \ Av.\ speed = 160km/h\end{lgathered}
⇢Average speed=
t
1
+t
2
d
1
+d
2
⇢Av. speed=
6+4
800+800
⇢ Av. speed=
10
1600
⇢ Av. speed=160km/h
ㅤ Hence-‾\;\;\underline{\textbf{\textsf{ Hence-}}}
Hence-
The average speed of the train is 160km/hr‾.\underline{\textsf{ The average speed of the train is \textbf{160km/hr}}}.
The average speed of the train is 160km/hr
.
━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━